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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Antony Gabagul
Antony Gabagul
9,351 Points

Weird error

Hi, Just wondering what seems to be an issue with this code since I keep getting errors but my IDLE shows me the right solution.

Thanks!

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(our_string):
    split_string = our_string.lower().split(' ')
    our_dict = {}
    for word in split_string:
        if word in our_dict:
            our_dict[word] += 1
        else:
            our_dict.update({word:1})
    return our_dict

1 Answer

The problem is the split(' '). The code challenge is excepting you to write split(). Note that by passing no arguments, python assumes that you want to separate on spaces anyway. I can't tell you why it's failing, because both do the same thing. I suppose the code that validates the challenge is looking for the split() method without args and you have them, so you fail even though your solution is correct. Just my assumption though.