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iOS Swift Basics (retired) Control Flow For-In Loop

Andrey Mitko
Andrey Mitko
19,127 Points
Posted by Andrey Mitko
Andrey Mitko
19,127 Points

What?!

Haha, where is my problem? ;)

for_loops.swift 
for i in 1...10 {
let i7 = i * 7 
println("\(i) * 7 = \(i7) \n")
}

1 Answer

Steve Hunter
Steve Hunter
57,712 Points

Hi Andrey,

You're very close - have a look through this:

for i in 1...10{
  println("\(i) * 7 = \(i * 7)")
}

You have the for loop implemented correctly but your handling of the string isn't quite right. I've interpolated \(i) and \(i * 7) and used println to make sure there's a new line inserted. (New swift doesn't use println but the keyword print includes a new line by default).

I think the additional new line was what the compiler was complaining about with your code.

I hope that helps,

Steve.

Steve Hunter
Steve Hunter
57,712 Points

The error I get with your code is:

 Bummer! You didn't println the right values. You printed [1 * 7 = 7 , 2 * 7 = 14 , 3 * 7 = 21 , 4 * 7 = 28 , 5 * 7 = 35 , 6 * 7 = 42 , 7 * 7 = 49 , 8 * 7 = 56 , 9 * 7 = 63 , 10 * 7 = 70 ], but we were looking for [1 * 7 = 7, 2 * 7 = 14, 3 * 7 = 21, 4 * 7 = 28, 5 * 7 = 35, 6 * 7 = 42, 7 * 7 = 49, 8 * 7 = 56, 9 * 7 = 63, 10 * 7 = 70].

The additional bit of whitespace in between the result of the multiplication and the comma seems to be the issue.

Removing the space and the additional newline caused by the \n and your code is fine.

[EDIT] - no, it is just the \n that's causing the problem.