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Eric Grant
2,453 PointsWhat am I doing wrong?
Do I times my variable by 2 to get the even-only numbers?
while ( var i = 1; i <= 24; i += 1 ) {
console.log(i * 2);
}
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2 Answers
Jason Anello
Courses Plus Student 94,610 PointsHi Eric,
First off, you're likely getting a a parse error since you used the while keyword. You likely meant to do a for loop.
In the for loop, i can be initialized to whatever number you want. It doesn't have to start at 1. So in this case, you can check the existing log statements and see that it starts at 2.
You have to go up to and including 24 so you have your conditional part correct.
The next thing is that you're incrementing by 1 but you can increase or decrease the value of i by any amount that you want so you can do what is convenient for this problem. To go from one even number to the next one, you have to add 2.
Now you've got the for loop generating the exact values that you need and there's no need to do any calculation inside your console.log statement.
Trevor Johnson
14,427 PointsHey Eric, I would solve this by starting i at 0 and increasing i by 2 on each loop and then console.log(i) each time through. That will print every even number.
Eric Grant
2,453 PointsThank you