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JavaScript Interpolation

Posted by Nick Trabue
Nick Trabue
Courses Plus Student 12,666 Points

What am I doing wrong with template literals?

So I was really excited to start playing with template literals and I wanted to apply it to a project that I'm currently working on. I'm relatively new at Javascript so it's probably something really simple that I'm missing.

This was what I had and it worked:

    for (var i=0; i<salesList.length; i++ ){
        loListing += '<div class="thumbnail text-center">'
        loListing += '<a href="'+salesList[i].lo_url+'"><img src="../'+salesList[i].lo_img+'" class="img-responsive" alt="Click to apply with '+salesList[i].lo_first_name +' '+ salesList[i].lo_last_name+'">'
        loListing += '<div class="caption">'
        loListing += '<p id="lo-caption">'+salesList[i].lo_first_name +' '+ salesList[i].lo_last_name+'</p>'
        loListing += '<p id="lo-link">Apply with '+salesList[i].lo_first_name+'</p>'
        loListing += '</div>'
        loListing += '</div>'
    }

This is what I tried using template literals. It only pulls the last object in the salesList array. The console log was just there for some troubleshooting but it does list all of the objects in the salesList array as expected:

    for (let i=0; i<salesList.length; i++){
        console.log(salesList[i]);
        loListing = `
            <div class="thumbnail text-center">
                <a href="${salesList[i].lo_url}">
                    <img src="../${salesList[i].lo_img}" class="img-responsive" alt="Click to apply with ${salesList[i].lo_first_name}!">
                    <div class="caption">
                    <p id="lo-caption">${salesList[i].lo_first_name} ${salesList[i].lo_last_name}</p>
                    <p id="lo-link">Apply with ${salesList[i].lo_first_name}</p>
                </div>
            </div>
        `
    }

Thanks!

2 Answers

Steven Parker
Steven Parker
229,759 Points
Steven Parker
Steven Parker
229,759 Points

The templates are working fine.

But each time through the array, you re-assign loListing, replacing anything already in it. So when the loop finishes, it will contain only the last item.

Did you intend to append to it instead, as you were doing in the earlier version? ("loListing += ...")

Nick Trabue
Nick Trabue
Courses Plus Student 12,666 Points

Thank you, Steven. Every time through the loop it was resetting the loListing variable until it got to the last person in the loop. That makes perfect sense.

loListing =
\\Didn't work as intended.

loListing += 
\\Worked as intended.
Tomasz Cysewski
Tomasz Cysewski
2,736 Points
Tomasz Cysewski
Tomasz Cysewski
2,736 Points

amazing code, I wish you good luck