Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Aaron Fry
Aaron Fry
826 Points

What am I missing?

I have already tested this on other programs and it works. Please advise me if they want it done a certain way because I have asked a fellow friend who codes much bigger things and he doesn't see a problem.

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(random_string):
    final_dict = {}
    string_words = random_string.split(" ")
    for item in words:
        if item not in word_tracker:
            word_tracker[item.lower()] = 1  
        else:
            word_tracker[item.lower()] += 1
    return final_dict

2 Answers

Cheo R
Cheo R
37,150 Points

Running your code, I got the following errors:

NameError: name 'words' is not defined

fixed with changing words to string_words

NameError: name 'word_tracker' is not defined

fixed with word_track = {}
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(random_string):
    final_dict = {}
    word_tracker = {}
    string_words = random_string.split(" ")
    for item in string_words:
        print("Item is: {}".format(item))
        if item not in word_tracker:
            print("\t not in word_tracker, adding {}".format(item.lower()))
            word_tracker[item.lower()] = 1
            print(word_tracker)
        else:
            print("\tis in word_tracker, updating {}".format(item.lower()))
            print(word_tracker[item.lower()])
            word_tracker[item.lower()] = word_tracker[item.lower()] + 1
    return word_tracker

print(word_count("I do not like it Sam I Am"))  # {}
print(word_count("I do not like it Sam I Am") == {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1})  # False

Do you see what it's returning? Look at your code and trace it backwards. I added a few print statements, as you see, it never gets to the else branch.

Hi Aaron,

Several things I see here:

  1. You make a list called string_words and then try to iterate over "words" which is not defined. So, the correct statement should be: for item in string_words:
  2. You initialize final_dict but then use word_tracker as your dictionary. Replace all references to word_tracker with final_dict.
  3. When you make the above changes, it runs, but only finds a single instance of each word ( "I" should be found twice). This happens because you don't convert the random_string to lower case first. Instead, you only convert the key of the dictionary element to lower case. So when you iterate through the string_words (which contains capital "I" twice) your logic tests if item not in final_dict (which has all lower case keys), so the else statement is never executed.

Hope this helps!