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PHP PHP Basics Unit Converter Manipulating Numbers

Posted by phillip smith
phillip smith
1,681 Points

what am i missing here

what am i missing here

index.php 
<?php

//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
$floatOne = 1.5;

var_dump($integerOne + 5);
var_dump($integerTwo - 1);
?>

2 Answers

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,972 Points
KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,972 Points

In general it is best to avoid var_dump in challenges. The error you receive is Bummer: You haven't changed $integerOne. The value of $integerOne after var_dump is still 1. Likewise $integerTwo is still 2. You need to update these so that after the calculation the assigned value of $integerOne is 6 and the assigned value of $integerTwo is 1.

phillip smith
phillip smith
1,681 Points

so what does the code look like to change those as you described?

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,972 Points
KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,972 Points

You could do this:

<?php

//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
$floatOne = 1.5;

$integerOne += 5;
$integerTwo -= 1;

?>

which is short for this:

<?php

//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
$floatOne = 1.5;

$integerOne = $integerOne + 5;
$integerTwo = $integerTwo - 1;

?>