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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops Refactor Using a Loop

Posted by Alexandru Pescaru
Alexandru Pescaru
6,410 Points

what am i missing here ?

?

script.js 
for ( var i = 1; var i <= 24; var += 2 ) {
console.log(var);
}
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

1 Answer

Steven Parker
Steven Parker
231,268 Points
Steven Parker
Steven Parker
231,268 Points

The keyword "var" should only be used once. The variable name is "i".

Then, the original code logged "all of the even numbers from 2 to 24", but this code logs the odd numbers from 1 to 23 instead (try starting with an even number).

Alexandru Pescaru
Alexandru Pescaru
6,410 Points

for ( var i = 2; i <= 24; i += 2 ) { console.log(); }

You didn't log out the even numbers from 2 to 24. what am i missing ?

Steven Parker
Steven Parker
231,268 Points
Steven Parker
Steven Parker
231,268 Points

You forgot to pass the variable "i" as the argument :point_right: console.log(i);