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Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today. # What am i missing on this challenge?

I thought i could change it so the values in the dictionary were the len(value) so the dictory would read { teacher: int} then i broke the dictionary into tuples so id have ordered lsit and then append them into my empty list.

teachers.py
```# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dict):
teacher_count = 0
for teacher in dict:
teacher_count +=1
return teacher_count

def num_courses(dict):
courses = 0
for value in dict.values():
courses += len(value)
return courses

def courses(dict):
new_list = []
for value in dict.values():
new_list.extend(value)
return new_list

def most_courses(dict):
winning_teacher = ''
max_number = 0
for key, value in dict.items():
if len(value) > max_number:
max_number = len(value)
winning_teacher = key
return winning_teacher

def stats(dict):
tuple_list = []
for value in dict.values():
value = len(value)
for item in dict.items():
tuple_list.append(item)
return tuple_list
``` You have mixed things up a little bit. I wouldn't bother commenting on it, it seems like you've just got tired and mixed stuff up.

As I demonstrate here, you need to create a list of lists. This list consists of 2 item lists, the first is the name, the second is the number of courses. In the dictinionary, the key is responsible for the name, the courses' list can give you the number of courses, if you use the "len()" function.

Keep coding!

```def stats(dict):
tuple_list = []
for key, value in dict.items():
tuple_list.append([key, len(value)])
return tuple_list
```