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PHP Build a Simple PHP Application Wrapping Up The Project Objects

Posted by MUZ140610 Tinashe Marunda
MUZ140610 Tinashe Marunda
7,028 Points

What do you think: is 16661 a palprime? Assign the number property of $checker a value of 16661. Be sure to refresh the

My code seems to be correct but its not passing. What can i do?

palprimes.php 
<?php

include("class.palprimechecker.php");
$checker = new PalprimeChecker();

$checker->number = 16661;

echo "The number " .$checker->number." ";
if ($checker->isPalprime()) {
   echo "is a palprime.";
   exit;
} else {
   echo "is not a palprime.";
}

?>
Bill Pearce
Bill Pearce
2,694 Points

I think the only problem is that in the two echo statements you include the " a palprime" in each. I think they want that left as a separate echo after the condition.

Stefan Hoffmann
Stefan Hoffmann
24,811 Points

You certainly do not need the exit statement. Maybe that gets checked?

1 Answer

Juliette Tworsey
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Juliette Tworsey
Front End Web Development Techdegree Graduate 32,425 Points
Juliette Tworsey
.a{fill-rule:evenodd;}techdegree seal-36
Juliette Tworsey
Front End Web Development Techdegree Graduate 32,425 Points

I'm not sure if this will work, but try this:

<?php include('class.palprimechecker.php');

$checker=new PalprimeChecker(); $number=$checker->number=16661;

echo "The number ".$number." "; if($checker->isPalprime($number)) { echo "is a palprime"; } else { echo "is not a palprime"; }

?>