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JavaScript Gulp Basics Improving your Gulp Task Pipelines Putting Multiple Tasks Together

What does the return statement do in gulp.task?

For example here, without return statement this task does the same thing.

gulp.task('minifyScripts', ['concatScripts'], function() {
    return gulp.src('js/app.js')
        .pipe(uglify())
        .pipe(rename('app.min.js'))
        .pipe(gulp.dest('js'))
});

1 Answer

Seth Kroger
Seth Kroger
56,403 Points

Because of Node.js' asynchronous way of doing things. Without the return, gulp would set up the stream to run and immediately move on to the next task without waiting for it to finish. Returning the gulp stream lets gulp know it should wait for the task to finish before running tasks dependent on it.

https://github.com/gulpjs/gulp/blob/master/docs/API.md#gulptaskname--deps-fn

Thanks for answer