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Start your free trialKhambrel Davis
24,572 PointsWhat goes into the body of the function?
func mathOperation(differenceBetweenNumberbs: (a: Int,b: Int) -> Int) { return differenceBetweenNumberbs(a * b) }
/**
For this code challenge, let’s define a math operation as a function that
carries out some work on two integers and returns an integer as well. An
example is the function below, `differenceBetweenNumbers`, which takes two
integers and calculates the difference between the numbers. After calculating,
it returns the difference.
*/
func differenceBetweenNumbers(a: Int, b:Int) -> (Int) {
return a - b
}
// Enter your code below
1 Answer
Rasmus Rønholt
Courses Plus Student 17,358 PointsFirst of all you need to restructure your function to 1) take in not just one parameter of type function, but also the two integers that the function should evaluate, and 2) return an integer. I have used x an y to point out that the arguments passed in has absolutely nothing to do with the arguments in differenceBetweenNumbers - except for what you do with them inside the function mathOperation. The argument operation can be any other function that takes two integers as parameters and returns an integer - like differenceBetweenNumbers.
func mathOperation(operation: (Int,Int) -> Int, x: Int, y: Int) -> Int {
//do something with the arguments and return an integer
}
I will try to let you figure out for yourself "what goes into the body of the function" and how to call it. But if you can't make it work, ask again and I will elaborate...