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Start your free trialRODRIGO MARTINEZ
5,912 PointsWhat if i want to make a function out of it to be called later?
So given the array of names we should get all the names strrting with 'S' in a new array. What if i want to leave the whole code as a function to be called later when i need to get names with 'S'? The only problem i encountered is that when i call the function it gives me not only the array with the names with 'S' but also and 'undefined' afterwards. Where does that 'undefined' come from? Thanks for help
const names = ['Selma', 'Ted', 'Mike', 'Sam', 'Sharon', 'Marvin'];
// Result: ['Selma', 'Sam', 'Sharon'];
let namesWithS = [];
function namesWithSfunction() {
names.forEach((name) => {
if (name.charAt(0) === 'S') {
namesWithS.push(name);
}
});
console.log(namesWithS);
};
console.log(namesWithSfunction());
And here's what i get in the console
treehouse:~/workspace$ node iteration.js
[ 'Selma', 'Sam', 'Sharon' ]
undefined
1 Answer
Steven Parker
231,269 PointsThis function does not "return" anything, so when you call it inside a "console.log", the log displays "undefined".
You can easily convert it to return the list instead of logging it internally:
console.log(namesWithS); // replace this line...
return namesWithS; // with this
RODRIGO MARTINEZ
5,912 PointsRODRIGO MARTINEZ
5,912 PointsThanks so much Steven. I can't beleive i missed that. It was so obvious. Sorry, and thanks again.