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JavaScript

RODRIGO MARTINEZ
RODRIGO MARTINEZ
5,912 Points

What if i want to make a function out of it to be called later?

So given the array of names we should get all the names strrting with 'S' in a new array. What if i want to leave the whole code as a function to be called later when i need to get names with 'S'? The only problem i encountered is that when i call the function it gives me not only the array with the names with 'S' but also and 'undefined' afterwards. Where does that 'undefined' come from? Thanks for help

const names = ['Selma', 'Ted', 'Mike', 'Sam', 'Sharon', 'Marvin'];
    // Result: ['Selma', 'Sam', 'Sharon'];

let namesWithS = [];

function namesWithSfunction() { 
  names.forEach((name) => {
    if (name.charAt(0) === 'S') {
      namesWithS.push(name);
    }
  });
  console.log(namesWithS);
};

console.log(namesWithSfunction());

And here's what i get in the console

treehouse:~/workspace$ node iteration.js                                                                                
[ 'Selma', 'Sam', 'Sharon' ]                                                                                            
undefined                   

1 Answer

Steven Parker
Steven Parker
231,269 Points

This function does not "return" anything, so when you call it inside a "console.log", the log displays "undefined".

You can easily convert it to return the list instead of logging it internally:

  console.log(namesWithS);  // replace this line...
  return namesWithS;        // with this
RODRIGO MARTINEZ
RODRIGO MARTINEZ
5,912 Points

Thanks so much Steven. I can't beleive i missed that. It was so obvious. Sorry, and thanks again.