Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by Louis Gonzalez
Louis Gonzalez
607 Points

What is missing?

How do I do that?

Name.java 
// I have setup a java.io.Console object for you named console
String firstName = "Louis";
console.printf("<%s> can code in Java");

1 Answer

Jonathan Hermansen
Jonathan Hermansen
25,935 Points
Jonathan Hermansen
Jonathan Hermansen
25,935 Points

.printf take two arguments, a and b ( console.printf(a, b) ). You must specify what %s is as the second argument, b. This will be your firstName variable, and that should be your second argument. Also, you don't need <> around %s. Your code should look something like this:

String firstName = "Louis";
console.printf("%s can code in Java!", <your variable with your name in it>);