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# What is problem with my code? Only one condition should be printed but here each condition is being printed.

```// store each exercise in a string variable
\$exercise1 = 'Display "Hello World!"';
\$exercise2 = 'Convert Pounds to Kilograms';
\$exercise3 = 'Convert Kilograms to Pounds';
\$exercise4 = 'Convert Miles to Kilometers';
\$exercise5 = 'Convert Kilometers to Miles';
\$exercise6 = 'Month long string of the day';
\$exercise7 = 'String of the day with levels';
// create a variable containing the day of the week
\$day= date('N');
var_dump(\$day);
if(\$day==1)
echo \$exercise1;
if(\$day==2)
echo \$exercise2;
if(\$day==3)
echo \$exercise3;
if(\$day==4)
echo \$exercise4;
if(\$day==5)
echo \$exercise5;
if(\$day==6)
echo \$exercise6;
if(\$day==7)
echo \$exercise7;
```

You are missing your open and closing curly braces around each echo function after the if statements. Should be like so:

```if(\$day1==1)
{
echo \$exercise1;
}
```

If you notice on your code you have the following:

if(\$day==1)

echo \$exercise1;

In conditional statements, the basic structure is as follows:

```if (check condition 1) {
# some code here
} elseif (check condition2) {
# some code here
} else {
#some code here
}
```

you can check as many conditions as you wish in consecutive elseif statements.

else at the end checks what remains after if and elseif. I hope this is clear.