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JavaScript JavaScript and the DOM (Retiring) Traversing the DOM Child Traversal

Samuel Tolentino
Samuel Tolentino
22,463 Points
Posted by Samuel Tolentino
Samuel Tolentino
22,463 Points

what is the answer.

const section = document.querySelector('section'); let paragraphs = section.children; for (let i = 0; i < paragraphs.length; i += 1) { paragraphs[i].color = 'blue'; }

this is what I have, what am I doing wrong?

app.js 
const section = document.querySelector('section');
let paragraphs = section.children;
paragraphs[0].color = 'blue';
paragraphs[1].color = 'blue';
paragraphs[2].color = 'blue';
/*for (let i = 0; i < paragraphs.length; i += 1) {
  paragraphs[i].color = 'blue';
}*/
index.html 
<!DOCTYPE html>
<html>
    <head>
        <title>Child Traversal</title>
    </head>
    <body>
        <section>
            <p>This is the first paragraph</p>
            <p>This is a slightly longer, second paragraph</p>
            <p>Shorter, last paragraph</p>
        </section>
        <footer>
            <p>&copy; 2016</p> 
        </footer>
        <script src="app.js"></script>
    </body>
</html>

1 Answer

Umesh Ravji
Umesh Ravji
42,386 Points
Umesh Ravji
Umesh Ravji
42,386 Points

Hi Jason, the value of the CSS property has to be changed by using the style property of the element.

paragraphs[0].style.color = 'blue';