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Java Java Basics Getting Started with Java IO

What is the parameter to the printf function?

It's asking "Did you forget to pass the firstName parameter to the printf function?" and I can't seem to find the mistake in line 3 where it's asking me to do it

IO.java
// I have imported java.io.Console for you.  It is a variable called console.
String firstName = "Ilona";
   console.printf("Firstname: %s/n", firstName); 
   console.readLine("%s/n, firstName");
String lastName = "Sorokina";
   console.readLine("%s/n, lastName");
Tomasz Baranczuk
Tomasz Baranczuk
1,245 Points

You put the quote int the wrong place:

console.readLine("%s/n", firstName);

1 Answer

Sean M
Sean M
7,344 Points

You have entered:

console.readLine("%s/n, firstName");

But firstName should be outside the quotation marks:

console.readLine("%s/n", firstName);