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y mobix
289 PointsWhat is the problem
Make a new variable, var2, with "e" at index -2. Remember, negative indexes start at the right side of the iterable.
I put this code.
var1 = "hakket"
t = var1[5]
var2 = var1.index('e')
var2 = var1[-2]
Which one is correct?
var1 = ["x","a","b","c","e","t"]
var1[5]
var2 = var1.index("e")
3 Answers
Khambrel Davis
24,572 Pointsvar1 = [1,3,4,5,6,"t"]
var2 = ["f",2,6,7,"e",9]
The challenge is asking you to create a new list with "e" as the second to last item.
Dhruv Patel
8,287 Pointsvar1 = list("tttttt")
This is all there is to it. Since we know we want the 5th index to be a letter "t" then we know its length needs to be greater than 6, as indices start at 0. So I just made a list out the of the string with 6 "t"'s. Hope that helps.
Jose Luis Lopez
19,179 Pointsvar1 = "abcdet"
"t" is at index[5]
var2 = "abcdef"
if you count backwards, "e" is at negative -2 is all you have to do