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JavaScript AJAX Basics (retiring) jQuery and AJAX Handle AJAX failures with jQuery

Pitrov Secondary
Pitrov Secondary
5,121 Points
Posted by Pitrov Secondary
Pitrov Secondary
5,121 Points

What is wrong here?

Can someone help me with this one?

app.js 
$.get("missing.html", function(data) {
  $("#footer").html(data);
}).fail(
let jqXHR = new jqXHR;
);
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
</head>
<body>
  <div id="main">
    <h1>AJAX with jQuery</h1>
  </div>
  <div id="footer"></div>
  <script src="jquery.js"></script>
  <script src="app.js"></script>
</body>
</html>

2 Answers

deebird
deebird
7,558 Points

You need to pass a function to the fail method with the parameter. Currently you are just setting a variable.

$.get("missing.html", function(data) {
  $("#footer").html(data);
}).fail(function(jqXHR){
alert(jqXHR.statusText);
});