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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Tatiane Lima
Tatiane Lima
6,738 Points
Posted by Tatiane Lima
Tatiane Lima
6,738 Points

what is wrong in my code

/* THIS IS THE QUESTION After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results from calling the returnValue function. When you call the returnValue function, make sure to pass in any string you'd like for the parameter. */

function returnValue(singleArgument) {
  var echo = singleArgument;
  return echo;
}
returnValue(exemplo);

Mod note: Added formatting to the javascript code so we could see more easily

4 Answers

Jonathan Grieve
MOD
Jonathan Grieve
Treehouse Moderator 91,253 Points
Jonathan Grieve
Jonathan Grieve
Treehouse Moderator 91,253 Points

Let's walk through what the challenge is asking for.

First, create the function block

function returnValue(argument) {

 return argument;
}

So this function will take a string as a value and expects a return statement to return the value back to the function. Use the parameter as the return value.

Having done this you then declare a variable, outside of the function. Then assign a function call to the variable.

function returnValue(arg) {

  return arg;
}

var echo = returnValue("String");

Where the string is the argument that is passed into the function.

Good luck.

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

:point_right: The challenge says "After your newly created returnValue function..."

You should leave the function as it was in the previous task step. Then create the echo variable below the function and not inside it.

You will assign the value to echo by calling the function, something like this:

let echo = returnValue("some string");
Tatiane Lima
Tatiane Lima
6,738 Points
Tatiane Lima
Tatiane Lima
6,738 Points

I already know the correct answer:

function returnValue(singleArgument) { return singleArgument; } var echo = returnValue("example");

But the message of error of this question wasn't helpful :(