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JavaScript AJAX Basics (retiring) jQuery and AJAX The Office Status Project Revisited

ARNAB ROY
PLUS
ARNAB ROY
Courses Plus Student 5,515 Points
Posted by ARNAB ROY
ARNAB ROY
Courses Plus Student 5,515 Points

What is wrong in the following Code.

Hi coded like this way but its not displaying the status of employee in the output. Please let me know what is the error on the code...

$(document).ready(function(){
  var url="../data/employees.json";
  $.getJSON(url,function(response(){
    var statusHtml='<ul class="bulleted">';
    $.each(response,function(index,value){
      var name=value.name;
      var status=value.inoffice;
      if(status===true){
        statusHtml+='<li class="in">';
      }else{
        statusHtml+='<li class="out">';
      }
      statusHtml+=name+'</li>';
    });
    statusHtml+='</ul>';
    $("#employeeList").html(statusHtml);
  }));//end GetJSON

});//End Ready

1 Answer

James Spence
James Spence
17,563 Points
James Spence
James Spence
17,563 Points

You have an extra pair of brackets, it should look like this:

$.getJSON(url,function(response){
   // code...

});//end GetJSON
Dave McFarland
Dave McFarland
Treehouse Teacher
Dave McFarland
Dave McFarland
Treehouse Teacher

+1 James Spence

ARNAB ROY, you have a couple of extra parentheses in your code: There's an extra ( right after response and an extra ) at the line ending with //end GetJSON