what is wrong number of prints

Question

import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while start == 0:
    num = random.randint(1,99)
    if even_odd(num) == True:
        print("is even")
    else:
        print ("is odd")
    start = start-1
```even.py
import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while start == 0:
    num = random.randint(1,99)
    if even_odd(num) == True:
        print("is even")
    else:
        print ("is odd")
    start = start-1    
```

Steven Parker · Accepted Answer

If you look at these two lines:
py
start = 5
while start == 0:

You can see that "start" will be 5 when the loop tests to see if it is equal to 0, so the loop will never run.
You could change the comparison, but even easier than that is to take advantage of the fact that a number that is not zero is considered "truthy" and just test it by naming it:
py
while start:

Similarly, you never have to compare anything to "True" — you can just name it.

Rujuta Shinde · Answer

Thanks! that helped

Rujuta Shinde · Answer

import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while start:
    num = random.randint(1,99)
    ans= even_odd(num)
    if ans == 0:
        print("{} is even".format(num))
    else:
        print ("{} is odd".format(num))
    start = start-1    
This too gives an incorrect answer
Some or all of your prints are wrong

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Rujuta Shinde

Rujuta Shinde

what is wrong number of prints

3 Answers

Steven Parker

Steven Parker

Rujuta Shinde

Rujuta Shinde

Steven Parker

Steven Parker

Rujuta Shinde

Rujuta Shinde