Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Python Python Basics (2015) Letter Game App Even or Odd Loop

what is wrong with my code

Any tips

even.py
import random
start = 5
while start > 0:
    num = random.randint(1, 99)
    if even_odd(num):
        print("{} is even".format(num))
    else:
        print("{} is odd".format.(num))
    start = start - 1
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! There are a couple of errors here, and one of them is about placement and the other is about syntax. You're trying to call even_odd before it's defined. You should leave the even_odd function where it was in the beginning and add your code below.

In the second print statement, you have a syntax error because there's an extraneous period/full stop:

#You wrote

print("{} is odd".format.(num))

#It should be

print("{} is odd".format(num))

Note the removal of the period/full stop between format and (num).

Hope this helps! :sparkles: