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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Posted by Jose Gonzalez
Jose Gonzalez
5,032 Points

What is wrong with my Code?

** Here is the error I am getting ** Bummer! Hmmm. It doesn't look like you're storing the returned value in the echo variable.

script.js 
function returnValue( arg1 ) {
  var echo = arg1;
  return arg1;
}

returnValue('My argument');
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

3 Answers

Rich Donnellan
MOD
Rich Donnellan
Treehouse Moderator 27,671 Points
Rich Donnellan
Rich Donnellan
Treehouse Moderator 27,671 Points

Jose,

You weren't supposed to alter the function in the second challenge question. This question only asks you to store the function's return value in a variable named echo. You can do so like this:

var example = someFunction(parameter);

Hopefully this will help you without giving you the answer.

–Rich

Jose Gonzalez
Jose Gonzalez
5,032 Points
Jose Gonzalez
Jose Gonzalez
5,032 Points

Thanks for the reply Rich. I swear I tried that first, and then a million other variants. I still cannot get it to work. here is what I have now: function returnValue(par1) { return par1; var echo = returnValue('My argument'); }

I have not had a problem so far with this course at all, but for some reason, I'm just not seeing the problem. Any more suggestions?

Jose Gonzalez
Jose Gonzalez
5,032 Points
Jose Gonzalez
Jose Gonzalez
5,032 Points

Just got it working. The var needs to be outside the curly braces.

Thanks again, Rich. You are a Rock star!