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Brandon Vera
672 PointsWhat is wrong with my code? Can someone help me?:( I'm stuck
I am multiplying the right variables but the challenge tells me im not
<?php
//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
$floatOne = 1.5;
$integerOne= $integerOne + 5;
echo ($integerOne);
$integerTwo=$integerTwo - 1;
echo ($integerTwo);
$mult=$integerOne*$floatOne;
echo ($mult);
?>
5 Answers
Antonio De Rose
20,884 Points<?php
//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
$floatOne = 1.5;
$integerOne= $integerOne + 5;
echo ($integerOne);//why is this needed, question have not asked so.
$integerTwo=$integerTwo - 1;
echo ($integerTwo);//why is this needed, not necessary.
$mult=$integerOne*$floatOne;//why is it stored in the variable, can you try echo along with multiply
echo ($mult);//then take off this line
Antonio De Rose
20,884 Points<?php
//first use markdownsheets, when you paste code
//Place your code below this comment
$integerOne = 1; $integerTwo = 2; $floatOne = 1.5;
$integerOne= $integerOne + 5; echo ($integerOne);//I already told you take this echo
$integerTwo=$integerTwo - 1; echo ($integerTwo);//this echo too, I already told take it from here
echo $integerOne*$floatOne; ?>
Brandon Vera
672 PointsThank you! Problem solved
Antonio De Rose
20,884 Pointssend me the new code, you are trying
Brandon Vera
672 Points<?php
//Place your code below this comment $integerOne = 1; $integerTwo = 2; $floatOne = 1.5;
$integerOne= $integerOne + 5; echo ($integerOne);
$integerTwo=$integerTwo - 1; echo ($integerTwo);
echo $integerOne*$floatOne; ?>
Multiplication is supposed to be a 9
Phil Rice
5,536 Pointsi got stuck on this also and the only thing that seemed to work is :
echo $integerOne*$floatOne;
I dont think the question is very well worded though : "Multiply $integerOne by $floatOne and display the results."
which suggests you perform the operation of multiplying $integerOne by $floatOne and then you display the results rather than displaying the results of $integerOne multiplied by $floatOne - a subtle difference, but confusing when it only accepts a single way of doing things.
Jayson Santos
Courses Plus Student 584 PointsPlease help, I still could not go out with this code challenge.
Thanks
Antonio De Rose
20,884 PointsHi Jayson,
Please send me the code.
Anton
Brandon Vera
672 PointsBrandon Vera
672 PointsChallenge Tast 3 of 3 Multiply $integerOne by $floatOne and display the results.
Bummer! Are you sure you multiplied $integerOne by $floatOne? This should be the same as 6*1.5 which equals 9.
Thats what it says... If i take the 2nd and 3rd paragraph off, it shows an error that task 2 have an error
Brandon Vera
672 PointsBrandon Vera
672 PointsAlready tried the echo along with the multiplication but same error ocurr: Are you sure you multiplied $integerOne by $floatOne? This should be the same as 6*1.5 which equals 9.