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Ray Hiera
1,870 PointsWhat is wrong with the code i made to solve the fizz buzz problem?? The compiler asks me to enter a , in the loop
func fizzBuzz(n: Int) -> String { // Enter your code between the two comment markers
for (n in 1...100 ) {
if (n % 3 == 0 ) && ( n % 5 == 0 ) {
return ("FizzBuzz")
} else if ( n % 3 == 0 ) {
return ("Fizz")
} else if ( n % 5 == 0 ) {
return ("Buzz")
}
} else // End code return ("(n)") }
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for (n in 1...100 ) {
if (n % 3 == 0 ) && ( n % 5 == 0 ) {
return ("FizzBuzz")
} else if ( n % 3 == 0 ) {
return ("Fizz")
} else if ( n % 5 == 0 ) {
return ("Buzz")
}
} else
// End code
return ("\(n)")
}
1 Answer
jcorum
71,830 PointsRay, it seems you put the for loop inside the function. But since it calls the function you want it outside the function:
func fizzBuzz(n: Int) -> String { //this is the function
if n % 3 == 0 && n % 5 == 0 {
return "FizzBuzz"
} else if n % 3 == 0 {
return "Fizz"
} else if n % 5 == 0 {
return "Buzz"
} else {
return "\(n)"
}
}
for n in 1...100 { //this is where you call the function with a range
fizzBuzz(n)
}
Try copying this and pasting it in a playground, and then experiment by changing the range.
To see the output in the console, at the bottom of the playground, change the call from fizzBuzz(n) to print(fizzBuzz(n))