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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Atıl Kurtulmuş
Atıl Kurtulmuş
4,945 Points
Posted by Atıl Kurtulmuş
Atıl Kurtulmuş
4,945 Points

What is wrong with this code?

works perfectly on pycharm workshop is being stubborn again

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    splitted = (string.lower()).split(" ")
    dic = {}
    for word in splitted:
        counted = splitted.count(word)
        dic[word] = counted

    return dic
Zach Anderson
Zach Anderson
3,691 Points
Zach Anderson
Zach Anderson
3,691 Points

I had this issue as well. Your code works... but there's another very specific gotcha they don't make very clear. The test/evaluation script will pass a test string (or maybe more... we'll never know!) into the function and compare it to see if you did it right.

What isn't clear in this exercise is that the test string will use other whitespace characters... not just spaces. ~Technically~ they request the words and do not specify at all what type of whitespace will separate the words. It was my assumption that it would be testing with a similarly clean sentence like the example.

So .split(" ") needs to be .split() which splits against ANY whitespace character including newline and whatnot.

Please mark this as an answer if it helped. Happy coding! -Zach