What is wrong with this code

Question

String firstName = console.readLine("What is your name? "); String lastname = "Dangol" String lastname = console.readLine;

IO.java

// I have imported java.io.Console for you.  It is a variable called console.

String firstName = console.readLine("What is your name?  ");
String lastname = "Dangol"
String lastname = console.readLine;

Answer 1 · 2018-02-24T17:46:29Z

February 24, 2018 5:46pm

Delete your second line, and make the lastName var do something similar to your firstName var.

String firstName = console.readLine("What is your first name?  ");
String lastName = console.readLine("What is your last name?  ");

Answer 2 · 2018-02-24T17:54:16Z

February 24, 2018 5:54pm

Hi,

You need to use "console.readLine ()" to get the lastName from the user.

Here's the solution :

String firstName = console.readLine("What is your First Name?  ");
String lastName = console.readLine("What is your Last Name?");

Challenge wants you to create a variable lastname in camelCase like this "lastName".

and then to use console.readLine() method just like you used to get firstName , to get the lastName in this part.

console.readLine() will print whatever you wrote in the parentheses("What is your Last Name") on the console and will wait for user to enter anything , and will return whatever user typed in as his last name. So we store that returned value in a string named "lastName".

I hope it answers your question, Happy Coding :)

Zain

Answer 3 · 2018-02-25T05:23:22Z

February 25, 2018 5:23am

You cant create two variables with same name and same type. String lastName="Dangal";//in this line you've missed a semicolon String lastName =console.readLine();//missing parentheses. both statements at once wont compile,it may cause compile error variable lastName is already defined ,therefore select one statement according to your need.

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Abhishek Dangol

Abhishek Dangol

What is wrong with this code

3 Answers

Jeff Wilton

Jeff Wilton

zainsra7

zainsra7

Fathima Fas-ha

Fathima Fas-ha