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Python Python Collections (2016, retired 2019) Sets Set Math

Praveen Chengalathu
Praveen Chengalathu
1,190 Points
Posted by Praveen Chengalathu
Praveen Chengalathu
1,190 Points

What is wrong with this function ?

COURSES = { "Python Basics": {"Python", "functions", "variables", "booleans", "integers", "floats", "arrays", "strings", "exceptions", "conditions", "input", "loops"}, "Java Basics": {"Java", "strings", "variables", "input", "exceptions", "integers", "booleans", "loops"}, "PHP Basics": {"PHP", "variables", "conditions", "integers", "floats", "strings", "booleans", "HTML"}, "Ruby Basics": {"Ruby", "strings", "floats", "integers", "conditions", "functions", "input"} } def covers(input_set): my_courses = [] for course in COURSES.keys(): if input_set.issubset(COURSES[course]): #print(COURSES[course]) my_courses.append(course) return my_courses

print(covers({"HTML"}))

sets.py 
COURSES = {
    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}
}

def covers(input_set):
    my_courses = []
    for course in COURSES.keys():
        if input_set.issubset(COURSES[course]):
           my_courses.append(course)
    return my_courses

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Task 1 is to create a function that checks for any overlap between the sets. That would be when the sets have any elements in common. A subset is where one set contains all of the elements of the other set, which is too restrictive for this function. But keep it in mind for task 2.

For now you need a different method of comparing the set contents.