###### Nico Meyer

1,137 Points# What the correct code? Got it working but challenge don't accept answer.

In this task we're going to write a simple function that takes two numbers and returns the remainder of dividing one number by the other.

Step 1: Declare a function named getRemainder that takes two parameters, a and b, both of type Int, and returns the value, also of type Int, obtained by carrying out the operation a modulo b. In case you've forgotten, the modulo operator is also called the remainder operator.

Step 2: The local names of the parameters are convenient but they make it hard to figure out the meaning of the function when we call it. Add two external names - value, for the first parameter and divisor for the second.

```
// Enter your code below
func getRemainder(a value: Int, b divisor: Int) -> Int
{
return (value % divisor)
}
```

## 1 Answer

###### andren

28,430 PointsYou have the local and external names of the parameters the wrong way around. The parameters are meant to be called `a`

and `b`

locally and `value`

and `divisor`

externally. Also it's not really necessary to wrap the equation is parenthesis, though it won't produce an error either.

If you fix the code like this:

```
func getRemainder(value a: Int, divisor b: Int) -> Int // Swapped local and external names
{
return a % b // Change names to account for the above change
}
```

Then your code will pass task 1.

## Nico Meyer

1,137 Points## Nico Meyer

1,137 PointsThanks, that dit the trick. Appreciate the help

## josh kinney

1,576 Points## josh kinney

1,576 PointsWhy doesn't this pass the second part?

func getRemainder(value a: Int, divisor b: Int) -> Int { return a % b }

let result = getRemainder(a:10, b:3)