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Matthew Saul
11,354 PointsWhat will console log out in the following code?
The answer to the code written below is not making any sense to me. The question is as follows:
What will console log out in the following code?
var person = "Jim";
function whosGotTheFunc() {
person = "Andrew";
}
person = "Nick";
whosGotTheFunc();
console.log(person);
The quiz says that the answer is Andrew. Shouldn't the answer be Nick because person = "Nick"; was written above console.log(person); and after function whosGotTheFuc()?
Wasn't the global variable redefined as Nick?
Any input would be helpful.
Thanks!
3 Answers
Dino Paškvan
Courses Plus Student 44,108 PointsThe function whosGotTheFunc doesn't do anything until it's called.
And it's called after person = "Nick"; and before the console.log.
Once it's called, it sets the value of the global person variable to "Andrew" (because there's no var keyword in front of it, so it's not a local variable).
That's why the console.log prints out Andrew.
James Gill
Courses Plus Student 34,936 PointsFor a (big) clue, try putting "var" in front of both instances of "person", and then log it out to the console.
Matthew Saul
11,354 PointsGot it! Makes perfect sense! Thanks for clarification! I appreciate your help!