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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Marzoog AlGhazwi
Marzoog AlGhazwi
15,796 Points
Posted by Marzoog AlGhazwi
Marzoog AlGhazwi
15,796 Points

what wrong!!

I tried my code and it worked but I'm not passing the challenge

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(string):
    re_dict = {}
    keys = string.lower().split(" ")
    for item in keys:
        value = keys.count(item)
        if item not in re_dict:
            re_dict.update({item:value})
            continue
        else:
            pass
    return re_dict

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

There's a clue in the error message when it says to "Be sure you're ... splitting on all whitespace!"

To split on "all whitespace" the argument to "split" must be left empty. Giving a space argument causes it to split only on individual spaces.

Otherwise, good job! :+1: