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Jackie Jen
2,723 PointsWhat wrong with the result of sql
Table t1
id status date
1 accept 2014-07-01
2 progress 2014-07-24
3 progress 2014-06-18
4 accept 2014-06-26
5 progress 2014-07-31
6 progress 2014-08-22
SELECT id, status, max(date) FROM t1 GROUP BY status the ans is
id status max('date')
1 accept 2014-07-01
2 progress 2014-08-22
I have no idea what going wrong? the ans for status progress should have an id of number '6' instead of 2. can you please advice?
2 Answers

dpjvanvalderen
6,081 PointsWhat if you try to select the id of 6 and then try to echo the result. Do you get the results ok then? I know this is not the solution but just wanted to know for further helping.

Matthew Eaton
10,669 PointsHi Kenny!
What is the exact MySQL query you used?
I'd imagine to get the results you're after it should look something like this:
SELECT id, status, max(date) FROM [table name] WHERE status = 'progress'
Or substitute 'progress' for whichever status you need it to look up.
(and of course replace [table name] with the actual name of your table.)

Jackie Jen
2,723 PointsHi Matthew,
I have add in another column product_id since the id is use as primary key. The Result match now using below mysql query
SELECT id
, product_id
, status
, date
FROM [table_name] WHERE date
= (SELECT MAX(date
)FROM [table_name] WHERE status
='progress')
id product_id status max('date')
1 5543 accept 2014-07-01
2 6222 progress 2014-07-24
3 8532 progress 2014-06-18
4 1368 accept 2014-06-26
5 8421 progress 2014-07-31
6 8321 progress 2014-08-22
id product_id status date
2 8321 progress 2014-08-22
Thanks for giving me idea on using status='progress'..^^
Jackie Jen
2,723 PointsJackie Jen
2,723 PointsHi Valderen,
the echo result is correct SELECT
id
,status
, max(date
) FROMtest
WHEREid
='6'