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Python Dates and Times in Python Dates and Times Timedelta Minute

What's missing for this minutes.py code challenge?

I tried to take 2 time snapshots of "now" at a and b. Since there wasn't much change in minutes, I added 5 minutes to b just to see num_minutes would return a nonzero value. I took the time_delta of b-a in seconds -> converted to minutes by dividing by 60 -> and rounded using "round".

minutes.py
import datetime

def minutes():
    a = datetime.datetime.now()
    b = datetime.datetime.now() + datetime.timedelta(minutes=5)
    timedelta = b-a
    num_minutes = round(timedelta.total_seconds() / 60)
    return num_minutes

2 Answers

Mel Rumsey
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STAFF
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Mel Rumsey
Treehouse Staff

Hey michellewong5 you are not too far off here What we want to do is create a function with 2 arguments that will be datetimes. We can just call them a and b accordingly. def minutes(a, b): Then we want to subtract the smaller number from the larger as you have done it. timedelta = b-a then we can return the rounded timedelta.total_seconds()/60.

Great job on what you have done so far, there were just a few small things that needed to be changed. :) Keep up the great work and let us know if we can assist you further!

Ok, got it. Thank you Mel.