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# What's the logic of this syntax for '8' to be printed at the end?

I did the exercises but I don't understand very well how is 8 printed in this case.

I have this Do While code:

```i = Math.floor(Math.random() * 10);
do {
text += i + ' ';
i = Math.floor(Math.random() * 10);
text += i;

} while (i !== 8)
```

And the While code:

```i = Math.floor(Math.random() * 10);
while ( i !== 8) {
text += i + ' ';
i = Math.floor(Math.random() * 10);
text += i;
}
```

Anyway, I don't trully understand how is exactly the number 8 being printed when we use `text += i;` at the very end of the conditions, because we're declaring the `i` variable as a random number at the beginning, right? Could someone explain to me please? Thank you in advance ! :)

The "`text += i`" line adds the current randomly-chosen value to the end of the line. Only after that is done then the loop checks to see if that number was an "8". If so, it stops and the line can be printed (by code not shown here). Otherwise, the loop continues and more numbers are picked.

So since the loop is always checking to see if the last number added was "8", then you can be sure there will always be an "8" at the end of the line.

Now that second version picks one number before the loop starts, so there's a small chance (1 in 10) that the line will be totally empty because an "8" is picked first. But otherwise, it does the same as the first version.

So, the loop stores that number somehow, let's say, internally? That's how it's printed?

Edit: Yeah I was just playing with it, put 6 instead of 8 and the number 6 was printed at the end. The loop stores it I guess but it would be good to know why. Anyway, thank you very much for your answer!

From top to bottom.

-- You declare a random number and store it in the i variable

-- If the var i does not equal 8 --> your while loop will run and keeps running until it is 8

-- It then adds that variable to the text variable --> print/log that out

Correct me if i'm wrong here, I don't know where your your text variable is declared or its contents are logged out.