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Python Python Collections (2016, retired 2019) Dictionaries Word Count

What's worng with this code

Simply the code splits the given text into separate words and returns dictionary with the word as the keys and the value of how many times this word is in the list of the words/text.

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(text):
    text_arr = text.split(" ")
    counted_words = {}
    for word in text_arr:
        counted_words[word.lower()] = text_arr.count(word)

    return counted_words

1 Answer

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,860 Points

Hi Martin,

You've pretty much got it, with just one small thing. If you submit the code above, you get the Bummer message "Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!". The hint is here and has to do with Whitespace.

The challenge is wanting you to split on all whitespace, but you are splitting on only spaces. The split method can take a parameter on what to split. split(" ") splits on spaces. If you don't pass any arguments to the method, it will split on all whitespace.

Just fix up that small thing and the rest is good to go!

Nice work. :) :dizzy:

Thank you lady !