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![Jay Lee](https://secure.gravatar.com/avatar/76ccb7fa837220f8c043794cf4b0c929?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Jay Lee
Courses Plus Student 196 PointsWhat's wrong?
Please help me finding solution for this
// I have setup a java.io.Console object for you named console
String firstName = "jay";
console.printf(%s can code in Java!, firstName);
2 Answers
![Jonathan Grieve](https://uploads.teamtreehouse.com/production/profile-photos/601842/micro_twitterCover.png)
Jonathan Grieve
Treehouse Moderator 91,253 PointsYou need to pass in a string to the console.printf method. When you do that, Java is smart enough to know that there's a %s
format specifier in there to convert that variable into the value of the firstName
variable.
So simply put the text the first argument of printf in quotes. "". Good luck :)
![Mohammed AlShaiban](https://uploads.teamtreehouse.com/production/profile-photos/132440/micro_50287464_00101_0308_XLarge.jpg)
Mohammed AlShaiban
6,455 PointsYou forgot to put your string inside quotes
console.printf("%s can code in Java!", firstName);
![Jay Lee](https://secure.gravatar.com/avatar/76ccb7fa837220f8c043794cf4b0c929?s=60&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Jay Lee
Courses Plus Student 196 PointsThank you :)
Jay Lee
Courses Plus Student 196 PointsJay Lee
Courses Plus Student 196 PointsThank you for helping :)