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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Jay Lee
PLUS
Jay Lee
Courses Plus Student 196 Points

What's wrong?

Please help me finding solution for this

Name.java
// I have setup a java.io.Console object for you named console
String firstName = "jay";
console.printf(%s can code in Java!, firstName);

2 Answers

Jonathan Grieve
MOD
Jonathan Grieve
Treehouse Moderator 91,253 Points

You need to pass in a string to the console.printf method. When you do that, Java is smart enough to know that there's a %s format specifier in there to convert that variable into the value of the firstName variable.

So simply put the text the first argument of printf in quotes. "". Good luck :)

You forgot to put your string inside quotes

console.printf("%s can code in Java!", firstName);