Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Jay Lee
PLUS
Jay Lee
Courses Plus Student 196 Points

What's wrong?

Please help me finding solution for this

Name.java
// I have setup a java.io.Console object for you named console
String firstName = "jay";
console.printf(%s can code in Java!, firstName);

2 Answers

Jonathan Grieve
MOD
Jonathan Grieve
Treehouse Moderator 90,980 Points

You need to pass in a string to the console.printf method. When you do that, Java is smart enough to know that there's a %s format specifier in there to convert that variable into the value of the firstName variable.

So simply put the text the first argument of printf in quotes. "". Good luck :)

You forgot to put your string inside quotes

console.printf("%s can code in Java!", firstName);