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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Jay Lee
Jay Lee
Courses Plus Student 196 Points

What's wrong?

Please help me finding solution for this

// I have setup a java.io.Console object for you named console
String firstName = "jay";
console.printf(%s can code in Java!, firstName);

2 Answers

Jonathan Grieve
Jonathan Grieve
Treehouse Moderator 91,252 Points

You need to pass in a string to the console.printf method. When you do that, Java is smart enough to know that there's a %s format specifier in there to convert that variable into the value of the firstName variable.

So simply put the text the first argument of printf in quotes. "". Good luck :)

You forgot to put your string inside quotes

console.printf("%s can code in Java!", firstName);