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iOS Swift Functions and Optionals Optionals What is an Optional?

What's wrong ?

Using the if-let statement, assign the value from the search function to a constant named result. If the name was found, use println to print out the string "Found". When calling the search function, pass it the name "Doc".

my code is:

func search(#name: String) -> String? {
    let names = ["Doc","Grumpy","Happy","Sleepy","Bashful","Sneezy","Dopey"]
    for n in names {
        if n == name {
            return n
        }
    }
    return nil
}

if let result = search("Doc") {
    println("Found")
}```

2 Answers

Stone Preston
Stone Preston
42,016 Points

since name is an external parameter (you used #name in the function definition, which means there is an external parameter called name, and an internal parameter called name as well), you must include it in the function call:

func search(#name: String) -> String? {
    let names = ["Doc","Grumpy","Happy","Sleepy","Bashful","Sneezy","Dopey"]
    for n in names {
        if n == name {
            return n
        }
    }
    return nil
}

if let result = search(name: "Doc") {
    println("Found")
}

Thanks a lot!

'''html <p> func search(#name: String) -> String? { let names = ["Doc","Grumpy","Happy","Sleepy","Bashful","Sneezy","Dopey"] for n in names { if n == name { return n } } return nil }

if let result = search(name: "Doc") { println("Found") } </p> '''