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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by William Grayson
William Grayson
146 Points

What's wrong?

I just don't know, I'm out of ideas, please help me.. :(

even.py 
import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5

while start == True:
    numb = random.randint(1, 99)
    if numb % 2 == 0:
        print("{} is even".format(numb))
    else:
        print("{} is odd".format(numb))
    start -= 1

1 Answer

hamsternation
hamsternation
26,616 Points
hamsternation
hamsternation
26,616 Points

The problem here is with your while statement:

while start == True:

In the console, try assigning start to a number, say 5. Then type in >>> start == True

What do you get?

You'd get False

That's because while ints are truthy they're not exactly == True. That's why the comparison returns false.

To revise your statement, you could change your while statement to:

while start:

I know this looks the same, but in this case, the while loop evaluates the truthiness of the variable start. And when it goes down to 0, it becomes falsey.

Hope this helps!

:)