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PHP Build a Basic PHP Website (2018) Building a Media Library in PHP Working with _GET Variables

Alejandro Jerez
Alejandro Jerez
10,987 Points

Whats Wrong? Build a Basic PHP Website, Working with $_GET variables

I followed the video and when I click on the "Suggest" and "Books" part of the site I get this: Parse error: syntax error, unexpected ';' in /home/treehouse/workspace/catalog.php on line 11


<?php $pageTitle = 'Full Catalog';


if ($_GET["cat"] == "books"){ $pageTitle = "Books"; }else if($_GET["cat"] == "movies"){ $pageTitle = "Movies"; }else if($_GET["cat"] == "music"{ $pageTitle = "Music"; } } include("Includes/header.php"); ?>

<div class="section page"> <h1><?php echo $pageTitle; ?></h1> </div>

<?php include("Includes/footer.php"); ?>


3 Answers

Since the pasted in version didn't appear to keep your version very well, I redid it below, and fixed it up.

$pageTitle = 'Full Catalog';

if (isset($_GET["cat"])) {

    if ($_GET["cat"] == "books") { 
        $pageTitle = "Books"; 
    } else if ($_GET["cat"] == "movies") { 
        $pageTitle = "Movies"; 
    } else if($_GET["cat"] == "music" { 
        $pageTitle = "Music"; 




But I have a question, why do you need the if...else if... etc. Why not just this?

if (isset($_GET["cat"])) {
    $pageTitle = $_GET["cat"] ; 

and send the cat through in the query string capitalized. Or use the PHP ucfirst method pn receipt of cat.


(PHP 4, PHP 5, PHP 7) ucfirst β€” Make a string's first character uppercase

Because if they send through ?cat=Sausages that's what you'll get as a title even though there aren't any sausages in your library.....

I am having the exact same issue. Any help would be great.

Enrico Buntsel
Enrico Buntsel
11,038 Points

I have same issue, can you please help?