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marinmirosevic
3,279 Pointswhats wrong here?
whats wrong here?
thanks
number=6
number_1=number/2
def even_odd(number):
if int(number_1)==number_1:
True
else:
False
2 Answers
Steve Hunter
57,712 PointsHi there,
You just need to create the method here; don't worry yourself about declaring variables outside of the method.
You want to return True if a number is even. To test for this, use the mod operator, the % symbol. An even number will give zero with a_number % 2. The a_number variable is passed into the method as a parameter; you don't need to declare it outside of the method.
So, that gives us an if clause:
if a_number % 2 == 0:
return True
This is mutually exclusive, so the else: part writes itself; there can only be two outcomes:
if a_number % 2 == 0:
return True
else:
return False
Now we just need to put that in a method that takes a parameter (and sort the indenting):
def even_odd(a_number):
if a_number % 2 == 0:
return True
else:
return False
That should do it for you!
Steve.
marinmirosevic
3,279 Pointsthaks Steve
