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iOS Functions in Swift Adding Power to Functions Function Parameters

Posted by Hosni Berker
Hosni Berker
1,115 Points

Whats wrong with my code

I dont understand whats wrong

functions.swift 
// Enter your code below

func getRemainder(value a: Int, divisor b : Int) -->Int {

  let remainder = (a % b)
  return remainder

}

2 Answers

Heath Robertson
Heath Robertson
3,158 Points
Heath Robertson
Heath Robertson
3,158 Points

You don't need to create a constant in this function. You can just go:

func getRemainder(value a: Int, divisor b: Int) -> Int {
    return a % b
}

You would also not need to add the parentheses around a % b like you did

let remainder = (a % b)

Anyway, hope this helps :)

Hosni Berker
Hosni Berker
1,115 Points
Hosni Berker
Hosni Berker
1,115 Points

yep, it worked thanks a ton!