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Start your free trialRuiqi Mao
16,675 Pointswhat's wrong with my SQL?
Challenge Task 1 of 1
We will be writing ONLY the SQL query for this challenge. The library database contains a Media table with the columns media_id, title, img, format, year and category. It also contains a Genres table with the columns genre_id and genre. To join these tables, there is a Media_Genres table that contains the column media_id and genre_id Add to the following SELECT statement to JOIN the Media table and the Genres table using the joining table Media_Genres. SELECT * FROM Media WHERE media_id=3; NOTE: You will need to add the table to the WHERE clause so that the media_id column is not ambiguous.
My sql: SELECT * from media AS m JOIN Media_Genres AS MG ON m.media_id = MG.media_id JOIN genres AS g ON MG.genre_id = g.genre_id WHERE m.media_id=3;
I cannot past this test, can anyone help me with my sql code? Thanks!
1 Answer
Steven Parker
231,271 PointsYour code seems technically correct.
But I don't think this challenge wants you to use table aliases, try it without them:
SELECT * from Media
JOIN Media_Genres ON Media.media_id = Media_Genres.media_id
JOIN Genres ON Media_Genres.genre_id = Genres.genre_id
WHERE Media.media_id=3;
Ruiqi Mao
16,675 PointsRuiqi Mao
16,675 PointsSure!
https://teamtreehouse.com/library/integrating-php-with-databases/using-relational-tables/joining-tables