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Sergey Mangov
3,651 Pointswhat's wrong with my word_count function?
def word_count(string):
new_dict = {}
new_string=string.lower()
new_string_list = string.split()
for word in new_sting_list:
if word in new_dict:
new_dict[word] +=1
else:
new_dict[word] = 1
return new_dict
# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.
def word_count(string):
new_dict = {}
new_string=string.lower()
new_string_list = string.split()
for word in new_sting_list:
if word in new_dict:
new_dict[word] +=1
else:
new_dict[word] = 1
return new_dict
1 Answer
Russell Sawyer
Front End Web Development Techdegree Student 15,705 Pointsdef word_count(string):
new_dict = {}
new_string=string.lower()
new_string_list = string.split()
for word in new_string_list: # You have a typo. You need a r in string
if word in new_dict:
new_dict[word] +=1
else:
new_dict[word] = 1
return new_dict