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Marwan Bakr
7,579 PointsWhat's wrong with this code?
What's wrong here?
for (var i = 2; i<25 && i % 2 == 0; i++) {
console.log(i);
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
2 Answers
Tijo Thomas
9,737 PointsThe third statement in your for loop iterates i by one. Your code block executes and logs 2 to the console, but fails after that since i now becomes 3 (fails i % 2 == 0). Changing the third statement what's listed below would work.
i += 2
A better way to do this so you are not testing two conditions is:
// i gets increased by 2 every time through the loop and once it becomes 26 the loop will end.
for(var i = 2; i < 25; i += 2) {
console.log(i);
}
Jennifer Nordell
Treehouse TeacherHi there! You're pretty close here, but the setup for your for loop is incorrect. Remember that the middle section defines a range. When that condition first evaluates to false, the loop exits. You have as your range:
i < 25 && i % 2 == 0
Because the variable i starts with a value of 2, during the first iteration 2 is less than 25 and 2 is evenly divisible by 2. So the console.log executes and logs out the value 2. Then we increment 2 to 3. And here's where it fails. The value 3 is less than 2 but 3 is not evenly divisible by 2. Thus, the expression fails and the for loop exits.
Here's your hint: make the check for i being divisible by 2 inside the for loop with an if statement. If it evaluates to true, execute the console.log.
I believe you can get it with these hints, but let me know if you're still stuck!
Jennifer Nordell
Treehouse TeacherTijo Thomas makes an excellent point! You can just increment by 2 instead of doing the if statement I suggested. Either method will work!
