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Python

Posted by Andrew Lopes
Andrew Lopes
3,190 Points

When I put sab on weapon selection (for a test), it'll accept and bow will be the weapon.

Like:

from character import Character
p = Character()
Name: Andrew
Weapon ([S]word, [A]xe, [B]ow): sab
p.weapon
'bow'

Why? Is there an error at if/else statements ?

def get_weapon(self):
    weapon_choice = input("Weapon ([S]word, [A]xe, [B]ow): ").lower()
    if weapon_choice in 'sab':
      if weapon_choice == 's':
        return 'sword'
      elif weapon_choice == 'a':
        return 'axe'
      else:
        return 'bow'
    else:
        return self.get_weapon()

2 Answers

Kenneth Love
STAFF
Kenneth Love
Treehouse Guest Teacher
Kenneth Love
Kenneth Love
Treehouse Guest Teacher

Because "sa", "ab", and "sab" are all in the string "sab". Since "sab" isn't "s" or "a", both of which are tested against explicitly, it falls into the else and sets your weapon to the bow.

Van Sanders
Van Sanders
16,087 Points
Van Sanders
Van Sanders
16,087 Points

I'm sorry, I was cruising around the forum trying to help people but I noticed that this also happens with my code. I tried all other combinations of those letters and noticed that 'sab' is the only combination that is accepted by the code and treated as if I entered 'b'.

I'm curious now!