Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Brian Wang
Brian Wang
2,685 Points
Posted by Brian Wang
Brian Wang
2,685 Points

where am i doing wrong?

can anyone tell me why my codes are not working?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(a_string):
    string_dict = {}
    for word in a_string.split():
        if word in string_dict:
            string_dict[word] += 1
        else:
            string_dict[word] = 1
    return string_dict

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

You're really close.

But remember the challenge said, "The keys in the dictionary will be each of the words in the string, lowercased." It looks like you forgot to convert the string (or the words) to lower case.