Where am I making a mistake with console printf code?

Question

...java
String firstName = console.readLine("Dan");
String lastName = console.readLine("Phantom");
console.printf("First Name:%s");
....
```IO.java
// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine("Dan");
String lastName = console.readLine("Phantom");
console.printf("First Name:%s");
```

Jennifer Nordell · Accepted Answer

Hi there! In your console.printf you have a %s which tells Java that you want to insert the value of the variable here. But you have two variables. You must tell it which variable's value you want to insert there.  Here's an example:
```java
String student = "Alana";
String studentTwo = "Jennifer";
console.printf("Hi there, %s", student);
```
This would print out "Hi there, Alana", because we told it to use the value for the variable student.
Hope this helps! :sparkles:

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Alana Weaver

Alana Weaver

Where am I making a mistake with console printf code?

1 Answer

Jennifer Nordell

Jennifer Nordell

Alana Weaver

Alana Weaver