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iOS Protocols in Swift Creating Flexible Objects Using Protocols Protocol Oriented Programming Part 2

JaWaune Long
JaWaune Long
2,511 Points
Posted by JaWaune Long
JaWaune Long
2,511 Points

Where are we using distance?

We have this method in the Moveable protocol
func move(_ direction: Direction, by distance: Int)

But we didn't use the distance argument for anything in the method, what's the point of this?

2 Answers

Otto linden
Otto linden
5,857 Points
Otto linden
Otto linden
5,857 Points

Hello! In the move function and in the direction switch we case

position = Point(x: position.x, y: position.y + 1)

so first the direction which is x or y and then distance and that is in this case position.x and position.y + 1, so the x position stays the same and the y position + 1! Hope this helps! 🙂

rachelmcr
rachelmcr
10,426 Points
rachelmcr
rachelmcr
10,426 Points

It looks like the instructor meant to implement the function like this:

func move(_ direction: Direction, by distance: Int) {
     switch direction {
     case.up: position = Point(x: position.x, y: position.y + distance)
     case.down: position = Point(x: position.x, y: position.y - distance)
     case.right: position = Point(x: position.x + distance, y: position.y)
     case.left: position = Point(x: position.x - distance, y: position.y)
     }
}

My guess is that he just forgot to make use of that distance argument in the midst of writing out the implementation, instead using a fixed distance (of 1) for each direction.