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Java Java Objects Harnessing the Power of Objects Overload Methods

shu Chan
shu Chan
2,951 Points
Posted by shu Chan
shu Chan
2,951 Points

Where exactly is the default "1" being passed onto?

in the code

public void drive(int lapsleft) { lapsDriven+=lapsLeft; barCount-=lapsLeft; } public void drive() {drive(1);}

What parameter is the 1 taking by default? lapsLeft? lapsDriven?

1 Answer

andren
andren
28,558 Points
andren
andren
28,558 Points

The line drive(1) is just calling the drive(int lapsleft) with 1 as an argument. Which means that it ends up being passed to the lapsleft parameter.

Arguments (values passed into a function) is automcaitcally assigned to parameters based on position. So the first argument goes to the first parameter. Since 1 is the first argument and lapsleft is the first parameter 1 gets assigned to lapsleft.