Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift Functions and Optionals Optionals Review: Functions

where is the problem in my code

i think i am doing everything fine thanks

divisible.swift
func isDivisible(#dividend: Int, #divisor: Int) -> Bool {
    if dividend % divisor == 0 {
        return true
    } else {
        return false
    }
}



func isNotDivisible(#dividend: Int, #divisor: Int) -> Bool {
    if dividend % divisor == 0 {
        return true
    }
     return false
}

2 Answers

The algorithm for isDivisible and isNotDivisible seem to be exactly the same. Just by the name of the function I believe they should be opposites. Therefore try flipping the return values around in the isNotDivisible function.

if dividend % divisor == 0 {
   return false; // Switch from true to false
}
return true; // Switch from false to true
Dennis Parussini
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Dennis Parussini
Treehouse Project Reviewer

You can also use the != operator.

func isNotDivisible(#dividend: Int, #divisor: Int) -> Bool {
    if dividend % divisor != 0 {
        return true
    }
     return false
}